Engineering Board Exam Reviewer · Definite Integrals · medium

Evaluate: -π/2π/2≤ft(x5 x+ 2x )dx

1. π 3.142
2. π/2 1.571
3. 0
4. π/4 0.785

Answer

B. π/2 1.571

Solution

x5 x is an odd function, so its integral over the symmetric interval is 0. For the rest, 2x=1- 2x/2: -π/2π/2 2x,dx= 12≤ft[x- 2x/2 ]-π/2π/2= π2.

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