Engineering Board Exam Reviewer · Definite Integrals · medium

Evaluate: 0π/2 4x 2x,dx

1. π/16 0.196
2. π/64 0.049
3. 3 π/32 0.295
4. π/32 0.098

Answer

D. π/32 0.098

Solution

Use the Beta (Wallis) form: 0π/2 4x 2x,dx=(3·1)(1)/6·4·2·π/2=3/48·π/2=π/32.

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