Engineering Board Exam Reviewer · Definite Integrals · medium

Evaluate: 0πx2 x,dx

1. 2 π 6.28
2. - π -3.14
3. - 2 π -6.28
4. π2 9.87

Answer

C. - 2 π -6.28

Solution

Parts twice: x2 x,dx=x2 x+2x x-2 x. At π: 0+2π(-1)-0=-2π; at 0: 0. The value is -2π.

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