Engineering Board Exam Reviewer · Definite Integrals · hard

Evaluate: 0π/4 (1+ x),dx

1. π 2/8 0.272
2. π 2/4 0.544
3. 2/2 0.347
4. π/8 0.393

Answer

A. π 2/8 0.272

Solution

Let I= 0π/4 (1+ x),dx. Replacing x by π4-x turns the integrand into ≤ft(1+1- x/1+ x )= 2- (1+ x). Adding the two forms: 2I=π/4 2, so I=π 2/8.

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