Engineering Board Exam Reviewer · Definite Integrals · medium

Evaluate: 1e( x)3,dx

1. -6 + 2 e -0.563
2. 6 - e 3.282
3. 6 - 2 e 0.563
4. -2 + e 0.718

Answer

C. 6 - 2 e 0.563

Solution

Parts repeatedly: ( x)3dx=x≤ft[( x)3-3( x)2+6 x-6 ]. At x=e: e(1-3+6-6)=-2e; at x=1: -6. The value is -2e-(-6)=6-2e.

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