Engineering Board Exam Reviewer · Definite Integrals · medium

Evaluate: 0∞dx/x2+4x+13

  1. ≤ft(3/2 )3 0.328
  2. ≤ft(2/3 )3 0.196
  3. π/6 0.524
  4. ≤ft(3/2 ) 0.983

Answer

A. ≤ft(3/2 )3 0.328

Solution

Complete the square: x2+4x+13=(x+2)2+9. Then ≤ft[ 13 +2/3 ]0∞= 13≤ft( π2- 23 )= 13 32 0.328.

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