Engineering Board Exam Reviewer · Definite Integrals · easy

Evaluate: 0π/2 x/1+ 2x,dx

1. π/4 0.785
2. π/2 1.571
3. 2 0.693
4. π/8 0.393

Answer

A. π/4 0.785

Solution

Let u= x, du=- x,dx: 01du/1+u2= 1= π4.

More Definite Integrals questions

1. Evaluate: 0πx2 x,dx
2. Evaluate: 01 x3sqrt(1-x2),dx
3. Evaluate: 0∞dx/x2+4x+13
4. Evaluate: 1e( x)3,dx
5. Evaluate: -13≤ft|x2-x-2 |dx
6. Evaluate: 0π/4 (1+ x),dx
7. Evaluate: 0π/2 4x 2x,dx
8. Find the average value of f(x)=xsqrt(x2+9) on the interval [0,4].
9. Evaluate: 0∞x3e-2x,dx
10. Evaluate: 0π/2 5x,dx

All Definite Integrals questions