Engineering Board Exam Reviewer · Series Circuits · medium
In the series circuit shown, V=24 V, R1=10, , R2=2, , R3=36, , and R4=12, . Find the voltage across R3.
- 6 V
- 14.4 V
- 9.6 V
- 9 V
Answer
B. 14.4 V
Solution
RT=60, and I=V/RT=400 mA. Then VR3=IR3=(400 mA)(36, )=14.4 V.
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