Engineering Board Exam Reviewer · Series Circuits · medium

In the series circuit shown, V=48 V, R1=44, , R2=12, , and R3=24, . Find the voltage across R2.

  1. 7.2 V
  2. 16 V
  3. 40.8 V
  4. 6.26 V

Answer

A. 7.2 V

Solution

RT=80, and I=V/RT=600 mA. Then VR2=IR2=(600 mA)(12, )=7.2 V.

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