Engineering Board Exam Reviewer · Series Circuits · easy

In the series circuit shown, V=24 V, R1=36, , and R2=12, . Find the current in the circuit.

  1. 666.67 mA
  2. 250 mA
  3. 500 mA
  4. 750 mA

Answer

C. 500 mA

Solution

RT=36, +12, =48, . By Ohm's law, I=V/RT= 24 V48, =500 mA.

More Series Circuits questions

  1. In the series circuit shown, V=9 V, R1=48, , R2=15, , and R3=27, . Find the total resistance.
  2. In the series circuit shown, V=30 V, R1=800, , and R2=2.2 k . Find the total resistance.
  3. Three resistors R1=3 k , R2=2 k , and R3 are in series across a 12 V battery. A voltmeter across R2 reads 4 V. Find R3.
  4. In a series string across 48 V, the voltage across R1 is three times the voltage across R2, and nothing else is in the circuit. If R2=4 k…
  5. In the series circuit shown, V=60 V, R1=2, , R2=27, , R3=86, , and R4=5, . Find the voltage across R2.
  6. In the series circuit shown, V=48 V, R1=3, , R2=129, , and R3=60, . If R2 is accidentally short-circuited, what is the new current?
  7. The circuit shown has V=12 V, R1=60, , and R3=4, . The ammeter reads 100 mA. Find the unknown resistance Rx.
  8. Resistors of 10 k , 22 k , and 47 k are connected in series across a 12 V source. Find the voltage across the 22 k resistor.
  9. A 12 V battery and a 6 V battery are connected in series so that they aid each other, across a 9, resistor. Find the current.
  10. Two resistors in the ratio R1:R2=2:3 are connected in series across a 50 V source. What is the voltage across R2?

All Series Circuits questions