Engineering Board Exam Reviewer · Series Circuits · hard
In a series string across 48 V, the voltage across R1 is three times the voltage across R2, and nothing else is in the circuit. If R2=4 k , find the current.
- 3 mA
- 12 mA
- 1.2 mA
- 9 mA
Answer
A. 3 mA
Solution
V1=3V2 and V1+V2=48 V2=12 V. I=V2/R2=12/4000=3 mA.
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