Engineering Board Exam Reviewer · Series Circuits · hard
In the series circuit shown, V=48 V, R1=3, , R2=129, , and R3=60, . If R2 is accidentally short-circuited, what is the new current?
- 250 mA
- 149.53 mA
- 761.9 mA
- 372.09 mA
Answer
C. 761.9 mA
Solution
With R2 shorted, the remaining resistance is RT'=192, -129, =63, . The new current is I=V/RT'= 48 V63, =761.9 mA (it was 250 mA before).
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