Engineering Board Exam Reviewer · Series Circuits · medium

In the series circuit shown, V=30 V, R1=1 k , R2=23.4 k , and R3=5.6 k . Find the total power delivered by the source.

  1. 1 mW
  2. 30 mW
  3. 900 mW
  4. 10 mW

Answer

B. 30 mW

Solution

I=V/RT= 30 V30 k =1 mA. The source delivers P=VI=(30 V)(1 mA)=30 mW, which equals the total power dissipated by the resistors.

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