Engineering Board Exam Reviewer · Series Circuits · hard
Three resistors R1=3 k , R2=2 k , and R3 are in series across a 12 V battery. A voltmeter across R2 reads 4 V. Find R3.
- 4 k
- 1 k
- 6 k
- 2 k
Answer
B. 1 k
Solution
I=V2/R2=4/2000=2 mA. RT=12/0.002=6 k , so R3=6-3-2=1 k .
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