Engineering Board Exam Reviewer · Series-Parallel Circuits · medium
In the series-parallel circuit shown, V=56 V, R1=6, , R2=10, , and R3=40, . Find the total power dissipated in the circuit.
- 522.67 W
- 96 W
- 56 W
- 224 W
Answer
D. 224 W
Solution
IT=4 A, so PT=VIT=(56 V)(4 A)=224 W.
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