Engineering Board Exam Reviewer · Series-Parallel Circuits · hard
In the bridge circuit shown, V=12 V, R1=10, , R2=40, , R3=100, , and R4=800, . The detector R5 is removed (open circuit between B and C). Find the voltage VBC between points B and C.
- 259.74 mV
- 519.48 mV
- 779.22 mV
- 389.61 mV
Answer
B. 519.48 mV
Solution
With R5 removed, each side is a voltage divider. VB=VR3/R1+R3=10.91 V and VC=VR4/R2+R4=11.43 V. The magnitude of the difference is |VB-VC|=519.48 mV.
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