Engineering Board Exam Reviewer · Series-Parallel Circuits · hard
In the circuit shown, V=9 V, R1=10, , R2=10, , and RL=40, . By how many volts does the voltage across R2 fall when the load RL is connected? (Compare with the voltage across R2 with the load removed.)
- 250 mV
- 750 mV
- 500 mV
- 375 mV
Answer
C. 500 mV
Solution
Unloaded: V2=VR2/R1+R2=(9 V)10, /10, +10, =4.5 V. Loaded: VL=4 V (as before). The drop is 4.5 V-4 V=500 mV.
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