Engineering Board Exam Reviewer · Series-Parallel Circuits · medium
In the ladder network shown, V=18 V, R1=12, , R2=40, , R3=55, , and R4=5, . Find the total resistance seen by the source.
- 112,
- 56.58,
- 27.86,
- 36,
Answer
D. 36,
Solution
Start at the far end: R3+R4=60, . In parallel with R2: (40, )(60, )/40, +60, =24, . Add R1: RT=12, +24, =36, .
More Series-Parallel Circuits questions
- In the circuit shown, V=30 V, R1=10, , R2=6, , R3=9, , and R4=30, . Find the current through R4.
- In the circuit shown, V=23 V, R1=20, , R2=7, , R3=5, , and R4=4, . Find the total current supplied by the source.
- In the circuit shown, V=18 V, R1=8, , R2=3, , R3=3, , and R4=12, . Find the total resistance seen by the source.
- In the circuit shown, V=128 V, R1=20, , R2=30, , and RL=20, . Find the voltage across the load RL.
- In the circuit shown, V=60 V, R1=20, , R2=20, , and RL=5, . Find the voltage across the load RL.
- In the series-parallel circuit shown, V=56 V, R1=6, , R2=10, , and R3=40, . Find the total power dissipated in the circuit.
- In the series-parallel circuit shown, V=115 V, R1=8, , R2=60, , and R3=20, . How much power is dissipated by R2?
- In the series-parallel circuit shown, V=60 V, R1=10, , R2=30, , and R3=15, . Find the current through R3.
- In the series-parallel circuit shown, V=90 V, R1=6, , R2=40, , and R3=60, . Find the voltage across the parallel combination of R2 and R3.
- In the series-parallel circuit shown, V=108 V, R1=15, , R2=30, , and R3=20, . Find the voltage across R1.