Engineering Board Exam Reviewer · Series-Parallel Circuits · medium
In the series-parallel circuit shown, V=115 V, R1=8, , R2=60, , and R3=20, . How much power is dissipated by R2?
- 220.42 W
- 575 W
- 93.75 W
- 187.5 W
Answer
C. 93.75 W
Solution
V23=ITR23=(5 A)(15, )=75 V. So PR2= V232R2= (75 V)260, =93.75 W.
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