Engineering Board Exam Reviewer · Series-Parallel Circuits · medium
In the series-parallel circuit shown, V=60 V, R1=10, , R2=30, , and R3=15, . Find the current through R3.
- 1.5 A
- 2 A
- 1 A
- 4 A
Answer
B. 2 A
Solution
V23=ITR23=(3 A)(10, )=30 V. Then I3= V2315, = 30 V15, =2 A.
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