Engineering Board Exam Reviewer · Series-Parallel Circuits · hard
A 6, resistor and a 3, resistor are connected in parallel, and this pair is in series with a 4, resistor. The whole network dissipates 150 W. What is the supply voltage?
- 22.5 V
- 40 V
- 900 V
- 30 V
Answer
D. 30 V
Solution
RT=6·3/6+3+4=2+4=6, . From P=V2/RT: V=sqrt(PRT)=sqrt((150)(6))=30 V.
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