Engineering Board Exam Reviewer · Branch, Loop and Node Analyses · medium
In the circuit shown, I1=10 A, I2=5 A, R1=25, , R2=5, , and R3=10, . Use nodal analysis, with the bottom wire as the reference (0 V). Find the current through R2 (from A to B).
- 12.5 A
- 5 A
- 7.5 A
- 2.5 A
Answer
C. 7.5 A
Solution
Node A: I1=VA/R1+VA-VB/R2 10 A=VA/25, +VA-VB/5, . Node B: VA-VB/R2=VB/R3+I2 A-VB/5, =VB/10, +5 A. Solving: VA=62.5 V and VB=25 V. IR2=VA-VB/R2= 62.5 V-25 V5, =7.5 A.
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