Engineering Board Exam Reviewer · Branch, Loop and Node Analyses · medium

In the two-loop circuit shown, V1=24 V, V2=12 V, R1=15, , R2=6, , and R3=10, . (The battery V2 has its positive terminal at the bottom.) Find the current through R1 (taken as positive from left to right).

  1. 1.04 A
  2. 1.52 A
  3. 1.14 A
  4. 3.04 A

Answer

B. 1.52 A

Solution

Mesh 1: (R1+R2)I1-R2I2=V1 21, ,I1-6, ,I2=24 V. Mesh 2: -R2I1+(R2+R3)I2=+V2 -6, ,I1+16, ,I2=12 V. Solving, I1=1.52 A is the current in R1.

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