Engineering Board Exam Reviewer · Branch, Loop and Node Analyses · medium
In the two-loop circuit shown, V1=15 V, V2=12 V, R1=2, , R2=12, , and R3=4, . (The battery V2 has its positive terminal at the bottom.) How much power is dissipated by R2?
- 276.48 W
- 227.07 W
- 2.43 W
- 4.86 W
Answer
C. 2.43 W
Solution
Mesh 1: (R1+R2)I1-R2I2=V1 14, ,I1-12, ,I2=15 V. Mesh 2: -R2I1+(R2+R3)I2=+V2 -12, ,I1+16, ,I2=12 V. I1=4.8 A, I2=4.35 A, so IR2=I1-I2=450 mA and P=IR22R2=(450 mA)2(12, )=2.43 W.
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