Engineering Board Exam Reviewer · Branch, Loop and Node Analyses · medium
In the two-loop circuit shown, V1=30 V, V2=20 V, R1=2, , R2=12, , and R3=4, . (The battery V2 has its positive terminal at the bottom.) Find the current through R2 (taken as positive when it flows downward).
- 17 A
- 1 A
- 9 A
- 8 A
Answer
B. 1 A
Solution
Mesh 1: (R1+R2)I1-R2I2=V1 14, ,I1-12, ,I2=30 V. Mesh 2: -R2I1+(R2+R3)I2=+V2 -12, ,I1+16, ,I2=20 V. I1=9 A and I2=8 A. In R2, I1 flows downward and I2 flows upward, so IR2=I1-I2=1 A (downward if positive).
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