Engineering Board Exam Reviewer · Branch, Loop and Node Analyses · hard
In the circuit shown, I1=5 A, I2=1 A, R1=20, , R2=10, , and R3=5, . Use nodal analysis, with the bottom wire as the reference (0 V). Find the voltage at node B.
- 10 V
- 5 V
- 13.33 V
- 40 V
Answer
A. 10 V
Solution
Node A: I1=VA/R1+VA-VB/R2 5 A=VA/20, +VA-VB/10, . Node B: VA-VB/R2=VB/R3+I2 A-VB/10, =VB/5, +1 A. Solving: VA=40 V and VB=10 V.
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