Engineering Board Exam Reviewer · Branch, Loop and Node Analyses · medium
In the circuit shown, I1=6 A, I2=4 A, R1=25, , R2=5, , and R3=10, . Use nodal analysis, with the bottom wire as the reference (0 V). Find the current through R2 (from A to B).
- 6.25 A
- 1.5 A
- 1.25 A
- 4.75 A
Answer
D. 4.75 A
Solution
Node A: I1=VA/R1+VA-VB/R2 6 A=VA/25, +VA-VB/5, . Node B: VA-VB/R2=VB/R3+I2 A-VB/5, =VB/10, +4 A. Solving: VA=31.25 V and VB=7.5 V. IR2=VA-VB/R2= 31.25 V-7.5 V5, =4.75 A.
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