Engineering Board Exam Reviewer · Branch, Loop and Node Analyses · medium
In the circuit shown, I1=2 A, I2=1 A, R1=8, , R2=5, , and R3=2, . Use nodal analysis, with the bottom wire as the reference (0 V). Find the voltage at node B.
- 800 mV
- 400 mV
- 200 mV
- 600 mV
Answer
B. 400 mV
Solution
Node A: I1=VA/R1+VA-VB/R2 2 A=VA/8, +VA-VB/5, . Node B: VA-VB/R2=VB/R3+I2 A-VB/5, =VB/2, +1 A. Solving: VA=6.4 V and VB=400 mV.
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