Engineering Board Exam Reviewer · Branch, Loop and Node Analyses · hard
In the circuit shown, I1=8 A, I2=4 A, R1=25, , R2=5, , and R3=10, . Use nodal analysis, with the bottom wire as the reference (0 V). How much power is delivered by the current source I1?
- 160 W
- 400 W
- 200 W
- 800 W
Answer
B. 400 W
Solution
Node A: I1=VA/R1+VA-VB/R2 8 A=VA/25, +VA-VB/5, . Node B: VA-VB/R2=VB/R3+I2 A-VB/5, =VB/10, +4 A. Solving: VA=50 V and VB=20 V. The voltage across I1 is VA, so P=VAI1=(50 V)(8 A)=400 W.
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