Engineering Board Exam Reviewer · Strength of Materials · medium
A steel rod (E = 200 GPa) 18 mm in diameter and 2 m long carries an axial tensile load of 50 kN. What is its total elongation?
- 0.491
- 1.965
- 3.93
- 0.982
Answer
B. 1.965
Solution
A = π d2/4 = 254.47 mm2. = PL/(AE) = (50 × 1000 N)(2 × 1000 mm) / (254.47 mm2 × 200 × 1000 MPa) = 1.965 mm.
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