Engineering Board Exam Reviewer · Strength of Materials · easy

A solid circular rod 12 mm in diameter carries an axial tensile load of 30 kN. What is the normal stress in the rod?

  1. 66.31
  2. 208.33
  3. 0.27
  4. 265.26

Answer

D. 265.26

Solution

A = π d2/4 = π (12)2/4 = 113.1 mm2. = P/A = (30 × 1000 N) / 113.1 mm2 = 265.26 MPa.

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