Engineering Board Exam Reviewer · Strength of Materials · medium

A steel rod (E = 200 GPa) 16 mm in diameter and 1.5 m long carries an axial tensile load of 40 kN. What is its total elongation?

  1. 1.492
  2. 0.373
  3. 2.984
  4. 0.746

Answer

A. 1.492

Solution

A = π d2/4 = 201.06 mm2. = PL/(AE) = (40 × 1000 N)(1.5 × 1000 mm) / (201.06 mm2 × 200 × 1000 MPa) = 1.492 mm.

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