Engineering Board Exam Reviewer · Strength of Materials · easy
A solid circular rod 16 mm in diameter carries an axial tensile load of 40 kN. What is the normal stress in the rod?
- 198.94
- 49.74
- 156.25
- 0.2
Answer
A. 198.94
Solution
A = π d2/4 = π (16)2/4 = 201.06 mm2. = P/A = (40 × 1000 N) / 201.06 mm2 = 198.94 MPa.
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