Engineering Board Exam Reviewer · Engineering Mechanics · easy
A force of 75 N is applied perpendicular to a lever at a distance of 1.5 m from the pivot point. What is the moment of the force about the pivot?
- 50
- 76.5
- 225
- 112.5
Answer
D. 112.5
Solution
Moment = Force × perpendicular distance = 75 N × 1.5 m = 112.5 N· m.
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