Engineering Board Exam Reviewer · Engineering Mechanics · easy
A force of 60 N is applied perpendicular to a lever at a distance of 0.9 m from the pivot point. What is the moment of the force about the pivot?
- 66.67
- 60.9
- 54
- 108
Answer
C. 54
Solution
Moment = Force × perpendicular distance = 60 N × 0.9 m = 54 N· m.
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