Engineering Board Exam Reviewer · Engineering Mechanics · medium

Two equal and opposite forces of 46 N each, separated by a perpendicular distance of 0.6 m, form a couple. What is the moment of this couple?

  1. 27.6
  2. 13.8
  3. 46.6
  4. 55.2

Answer

A. 27.6

Solution

The moment of a couple = Force × perpendicular distance between the forces = 46 N × 0.6 m = 27.6 N· m.

More Engineering Mechanics questions

  1. A force of 88 N is applied at the end of a 2 m lever arm, at an angle of 40° from the lever arm. What is the moment of the force about the…
  2. A force of 60 N is applied perpendicular to a lever at a distance of 0.9 m from the pivot point. What is the moment of the force about the…
  3. Two equal and opposite forces of 43 N each, separated by a perpendicular distance of 0.45 m, form a couple. What is the moment of this…
  4. A force of 84 N is applied at the end of a 1.5 m lever arm, at an angle of 30° from the lever arm. What is the moment of the force about…
  5. A force of 55 N is applied perpendicular to a lever at a distance of 0.7 m from the pivot point. What is the moment of the force about the…
  6. Two equal and opposite forces of 40 N each, separated by a perpendicular distance of 0.3 m, form a couple. What is the moment of this…
  7. A force of 80 N is applied at the end of a 1 m lever arm, at an angle of 20° from the lever arm. What is the moment of the force about the…
  8. A force of 50 N is applied perpendicular to a lever at a distance of 0.5 m from the pivot point. What is the moment of the force about the…
  9. A force has a horizontal component of 58 N and a vertical component of 62 N. What is the magnitude of the resultant force?
  10. Two concurrent forces, F1 = 130 N and F2 = 125 N, act on a particle with an angle of 90° between them. What is the magnitude of their…

All Engineering Mechanics Reviewer questions