Engineering Board Exam Reviewer · Engineering Mechanics · easy
A force of 65 N is applied perpendicular to a lever at a distance of 1.1 m from the pivot point. What is the moment of the force about the pivot?
- 59.09
- 71.5
- 66.1
- 143
Answer
B. 71.5
Solution
Moment = Force × perpendicular distance = 65 N × 1.1 m = 71.5 N· m.
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