Engineering Board Exam Reviewer · Engineering Mechanics · medium
A force of 96 N is applied at the end of a 3 m lever arm, at an angle of 60° from the lever arm. What is the moment of the force about the pivot at the other end of the arm?
- 144
- 249.42
- 288
- 498.83
Answer
B. 249.42
Solution
Moment = F × L × ( ) = 96 × 3 × (60°) = 249.42 N· m. Only the component of force perpendicular to the arm produces a moment.
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