Engineering Board Exam Reviewer · Engineering Mechanics · hard
A vertical load of 675 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 60° above the horizontal. Using the method of joints, what is the force in member AB?
- 1169.13
- 584.57
- 779.42
- 389.71
Answer
D. 389.71
Solution
First, Fy = 0 at joint A gives F(AC) = 675 / (60°) = 779.42 N. Then Fx = 0: F(AB) = F(AC) · (60°) = 779.42 × (60°) = 389.71 N.
More Engineering Mechanics questions
- A vertical load of 675 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 60° above the…
- A vertical load of 650 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 55° above the…
- A vertical load of 650 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 55° above the…
- A vertical load of 625 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 50° above the…
- A vertical load of 625 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 50° above the…
- A vertical load of 600 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 45° above the…
- A vertical load of 600 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 45° above the…
- A vertical load of 575 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 40° above the…
- A vertical load of 575 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 40° above the…
- A vertical load of 550 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 35° above the…