Engineering Board Exam Reviewer · Engineering Mechanics · medium
A vertical load of 575 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 40° above the horizontal. Using the method of joints, what is the force in member AC?
- 369.6
- 750.61
- 894.54
- 482.48
Answer
C. 894.54
Solution
At joint A, Fy = 0: F(AC) · (40°) = 575 N, so F(AC) = 575 / (40°) = 894.54 N.
More Engineering Mechanics questions
- A vertical load of 550 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 35° above the…
- A vertical load of 550 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 35° above the…
- A vertical load of 525 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 30° above the…
- A vertical load of 525 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 30° above the…
- A vertical load of 500 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 25° above the…
- A vertical load of 500 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 25° above the…
- A force of 75 N is applied perpendicular to a lever at a distance of 1.5 m from the pivot point. What is the moment of the force about the…
- Two equal and opposite forces of 52 N each, separated by a perpendicular distance of 0.9 m, form a couple. What is the moment of this…
- A force of 96 N is applied at the end of a 3 m lever arm, at an angle of 60° from the lever arm. What is the moment of the force about the…
- A force of 70 N is applied perpendicular to a lever at a distance of 1.3 m from the pivot point. What is the moment of the force about the…