Engineering Board Exam Reviewer · Engineering Mechanics · hard
A vertical load of 600 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 45° above the horizontal. Using the method of joints, what is the force in member AB?
- 424.26
- 600
- 848.53
- 648
Answer
B. 600
Solution
First, Fy = 0 at joint A gives F(AC) = 600 / (45°) = 848.53 N. Then Fx = 0: F(AB) = F(AC) · (45°) = 848.53 × (45°) = 600 N.
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