Engineering Board Exam Reviewer · Engineering Mechanics · medium
A vertical load of 650 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 55° above the horizontal. Using the method of joints, what is the force in member AB?
- 928.3
- 455.13
- 532.45
- 793.5
Answer
B. 455.13
Solution
First, Fy = 0 at joint A gives F(AC) = 650 / (55°) = 793.5 N. Then Fx = 0: F(AB) = F(AC) · (55°) = 793.5 × (55°) = 455.13 N.
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