Engineering Board Exam Reviewer · Engineering Mechanics · hard
A vertical load of 675 N hangs from joint A, which is supported by two members: AB, horizontal, and AC, inclined at 60° above the horizontal. Using the method of joints, what is the force in member AC?
- 584.57
- 1350
- 779.42
- 1169.13
Answer
C. 779.42
Solution
At joint A, Fy = 0: F(AC) · (60°) = 675 N, so F(AC) = 675 / (60°) = 779.42 N.
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