Engineering Board Exam Reviewer · Circles · medium

Find the equation of the circle with center (-1,4) that passes through (2,0).

1. x2 + 2 x + y2 - 8 y - 8 = 0
2. x2 - 2 x + y2 + 8 y - 8 = 0
3. x2 + 2 x + y2 - 8 y + 8 = 0
4. x2 + 2 x + y2 - 8 y - 17 = 0

Answer

A. x2 + 2 x + y2 - 8 y - 8 = 0

Solution

r=sqrt((2+1)2+(0-4)2)=5. (x+1)2+(y-4)2=25 x2+y2+2x-8y-8=0.

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