Engineering Board Exam Reviewer · Circles · medium

Find the center of the circle x2+y2-10x+4y+13=0.

  1. (-5,2)
  2. (5,2)
  3. (5,-2)
  4. (10,-4)

Answer

C. (5,-2)

Solution

Complete the squares: (x-5)2+(y+2)2=-13+25+4=16. The center is (5,-2).

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