Engineering Board Exam Reviewer · Circles · medium
Find the equation of the circle passing through (0,0), (4,0) and (0,6).
- x2 - 4 x + y2 - 6 y = 0
- x2 + 4 x + y2 + 6 y = 0
- x2 - 6 x + y2 - 4 y = 0
- x2 - 2 x + y2 - 3 y = 0
Answer
A. x2 - 4 x + y2 - 6 y = 0
Solution
Let x2+y2+Dx+Ey+F=0. (0,0) F=0; (4,0) 16+4D=0 D=-4; (0,6) 36+6E=0 E=-6.
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