Engineering Board Exam Reviewer · Circles · medium
Find the equation of the circle that has the segment joining (-2,3) and (6,-1) as a diameter.
- x2 - 4 x + y2 - 2 y - 5 = 0
- x2 + 4 x + y2 + 2 y - 15 = 0
- x2 - 4 x + y2 - 2 y - 15 = 0
- x2 - 4 x + y2 - 2 y - 20 = 0
Answer
C. x2 - 4 x + y2 - 2 y - 15 = 0
Solution
The center is the midpoint (2,1) and r2=≤ft( sqrt(82+42)2 )2=20. (x-2)2+(y-1)2=20 x2+y2-4x-2y-15=0.
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