Engineering Board Exam Reviewer · Circles · medium
Find the equation of the circle with center (3,-5) that is tangent to the x-axis.
- x2 - 6 x + y2 + 10 y + 25 = 0
- x2 + 6 x + y2 - 10 y + 9 = 0
- x2 - 6 x + y2 + 10 y + 9 = 0
- x2 - 6 x + y2 + 10 y + 29 = 0
Answer
C. x2 - 6 x + y2 + 10 y + 9 = 0
Solution
The radius equals the distance from the center to the x-axis: r=5. (x-3)2+(y+5)2=25 x2+y2-6x+10y+9=0.
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