Engineering Board Exam Reviewer · Integration by Substitution · medium
Evaluate: xsqrt(x2+9),dx
- 13(x2+9)3/2+C
- 23(x2+9)3/2+C
- 13(x2+9)1/2+C
- (x2+9)3/2+C
Answer
A. 13(x2+9)3/2+C
Solution
Let u=x2+9, du=2x,dx. 12 u,du= 12· 23u3/2+C= 13(x2+9)3/2+C.
Engineering Board Exam Reviewer · Integration by Substitution · medium
A. 13(x2+9)3/2+C
Let u=x2+9, du=2x,dx. 12 u,du= 12· 23u3/2+C= 13(x2+9)3/2+C.