Engineering Board Exam Reviewer · Integration by Substitution · easy

Evaluate: exe2 x + 1,dx

1. ≤ft(e2 x + 1 )2+C
2. ≤ft(e2 x )2+C
3. ≤ft(ex )+C
4. ex ≤ft(ex )+C

Answer

C. ≤ft(ex )+C

Solution

Let u=ex, du=ex,dx. Then /1+u2= (ex)+C.

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